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1// RUN: %clang_analyze_cc1 %s \2// RUN:   -analyzer-checker=core \3// RUN:   -analyzer-checker=debug.ExprInspection \4// RUN:   2>&1 | FileCheck %s5 6// In this test we check whether the solver's symbol simplification mechanism7// is capable of reaching a fixpoint. This should be done after one iteration.8 9void clang_analyzer_printState();10 11void test(int a, int b, int c) {12  if (a + b != c)13    return;14  clang_analyzer_printState();15  // CHECK:      "constraints": [16  // CHECK-NEXT:   { "symbol": "((reg_$0<int a>) + (reg_$2<int b>)) != (reg_$5<int c>)", "range": "{ [0, 0] }" }17  // CHECK-NEXT: ],18  // CHECK-NEXT: "equivalence_classes": [19  // CHECK-NEXT:   [ "(reg_$0<int a>) + (reg_$2<int b>)", "reg_$5<int c>" ]20  // CHECK-NEXT: ],21  // CHECK-NEXT: "disequality_info": null,22 23  // Simplification starts here.24  if (b != 0)25    return;26  clang_analyzer_printState();27  // CHECK:        "constraints": [28  // CHECK-NEXT:     { "symbol": "(reg_$0<int a>) != (reg_$5<int c>)", "range": "{ [0, 0] }" },29  // CHECK-NEXT:     { "symbol": "reg_$2<int b>", "range": "{ [0, 0] }" }30  // CHECK-NEXT:   ],31  // CHECK-NEXT:   "equivalence_classes": [32  // CHECK-NEXT:     [ "(reg_$0<int a>) != (reg_$5<int c>)" ],33  // CHECK-NEXT:     [ "reg_$0<int a>", "reg_$5<int c>" ]34  // CHECK-NEXT:   ],35  // CHECK-NEXT: "disequality_info": null,36 37  // Keep the symbols and the constraints! alive.38  (void)(a * b * c);39  return;40}41