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1// RUN: %clang_analyze_cc1 %s \2// RUN:   -analyzer-checker=core \3// RUN:   -analyzer-checker=debug.ExprInspection \4// RUN:   2>&1 | FileCheck %s5 6// In this test we check whether the solver's symbol simplification mechanism7// is capable of reaching a fixpoint. This should be done after TWO iterations.8 9void clang_analyzer_printState();10 11void test(int a, int b, int c, int d) {12  if (a + b + c != d)13    return;14  if (c + b != 0)15    return;16  clang_analyzer_printState();17  // CHECK:      "constraints": [18  // CHECK-NEXT:   { "symbol": "(((reg_$0<int a>) + (reg_$2<int b>)) + (reg_$5<int c>)) != (reg_$8<int d>)", "range": "{ [0, 0] }" },19  // CHECK-NEXT:   { "symbol": "(reg_$5<int c>) + (reg_$2<int b>)", "range": "{ [0, 0] }" }20  // CHECK-NEXT: ],21  // CHECK-NEXT: "equivalence_classes": [22  // CHECK-NEXT:   [ "((reg_$0<int a>) + (reg_$2<int b>)) + (reg_$5<int c>)", "reg_$8<int d>" ]23  // CHECK-NEXT: ],24  // CHECK-NEXT: "disequality_info": null,25 26  // Simplification starts here.27  if (b != 0)28    return;29  clang_analyzer_printState();30  // CHECK:       "constraints": [31  // CHECK-NEXT:    { "symbol": "(reg_$0<int a>) != (reg_$8<int d>)", "range": "{ [0, 0] }" },32  // CHECK-NEXT:    { "symbol": "reg_$2<int b>", "range": "{ [0, 0] }" },33  // CHECK-NEXT:    { "symbol": "reg_$5<int c>", "range": "{ [0, 0] }" }34  // CHECK-NEXT:  ],35  // CHECK-NEXT:  "equivalence_classes": [36  // CHECK-NEXT:    [ "(reg_$0<int a>) != (reg_$8<int d>)" ],37  // CHECK-NEXT:    [ "reg_$0<int a>", "reg_$8<int d>" ],38  // CHECK-NEXT:    [ "reg_$5<int c>" ]39  // CHECK-NEXT:  ],40  // CHECK-NEXT:  "disequality_info": null,41 42  // Keep the symbols and the constraints! alive.43  (void)(a * b * c * d);44  return;45}46