10 lines · c
1for (int c0 = 2; c0 < O; c0 += 1)2 for (int c1 = 3; c1 < 2 * N - 2; c1 += 2) {3 for (int c3 = 1; c3 <= M; c3 += 1) {4 S1(c0, (c1 + 1) / 2, c3);5 S2(c0, (c1 + 1) / 2, c3);6 }7 for (int c3 = 2; c3 < M; c3 += 1)8 S3(c0, (c1 + 1) / 2, c3);9 }10