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1# Check that isl recognizes that the inverse schedule is single-valued2# and does not end up in an infinite recursion.3[t1] -> {S[c2] -> [c2]: t1 <= c2 <= 134 and (c2+t1) % 128 = 0 and c2 > 0}4[t1] -> {: t1 > 0}5[t1] -> {}6 1# Check that isl recognizes that the inverse schedule is single-valued2# and does not end up in an infinite recursion.3[t1] -> {S[c2] -> [c2]: t1 <= c2 <= 134 and (c2+t1) % 128 = 0 and c2 > 0}4[t1] -> {: t1 > 0}5[t1] -> {}6